The trolleybus engine received 3000 kWh of energy from the network in 1 minute. Determine the coefficient of efficiency
| August 9, 2021 | education
The trolleybus engine received 3000 kWh of energy from the network in 1 minute. Determine the coefficient of efficiency of the engine, if during this time the useful work of 2400 kW • hour has been accomplished.
These tasks: t (duration of the trolleybus engine) = 1 min (1/60 h); W (energy received from the network) = 3000 kWh; Ap (useful work done by a tram) = 2400 kWh.
The efficiency of the engine of the considered trolleybus is calculated by the formula: η = Ap / W.
Let’s make a calculation: η = 2400/3000 = 0.8 or 80%.
Answer: The engine of the considered trolleybus has an efficiency of 80%.
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