The trolleybus, moving from a stop with an acceleration of 0.6 m / s2, covered a distance of 30 m

The trolleybus, moving from a stop with an acceleration of 0.6 m / s2, covered a distance of 30 m, what is its speed at the end of the route?

To find the value of the trolleybus speed at the end of the route from the stop, we will use the formula: S = Vк ^ 2 / 2а, whence Vк = √ (S * 2a).

Variables: S – the track covered by the trolleybus (S = 30 m); a – trolleybus acceleration (a = 0.6 m / s2).

Calculation: Vк = √ (S * 2a) = √ (30 * 2 * 0.6) = 6 m / s.

Answer: At the end of the route, the trolleybus had to reach a speed of 6 m / s.