The trolleybus traveled for the first half of the journey at a speed of 15 km / h, and the second half at a speed of 10 km / h.

The trolleybus traveled for the first half of the journey at a speed of 15 km / h, and the second half at a speed of 10 km / h. The average ground speed of the trolleybus is.

Task data: V1 (speed of this trolleybus in the first half of the journey) = 15 km / h; V2 (speed on the second half of the journey) = 10 km / h.

The average ground speed of this trolleybus is determined by the formula: V = S / (t1 + t2) = S / (S / 2V1 + S / 2V2) = 1 / (1 / 2V1 + 1 / 2V2).

Let’s make a calculation: V = 1 / (1 / (2 * 15) + 1 / (2 * 10)) = 12 km / h.

Answer: The average ground speed of this trolleybus is 12 km / h.



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