The tug has a capacity of 24480 l, s with a bollard pull of 2500 kN. What is the speed of its movement?

We express the speed of the tug from the power formula, assuming the speed of movement to be a constant value:

N = F * V, where N is the power of the tug (N = 24480 hp), F is the pulling force of the tug (F = 2500 kN = 2500 * 103 N), V is the required speed of the tug (m / s).

To carry out the calculations, let’s convert the power of the tug from horsepower to watts.

1 l. with. = 735.5 W.

24480 l. with. = 24480 * 735.5 = 18005040 W.

V = N / F = 18005040 / (2500 * 103) ≈ 7.2 m / s.

Answer: The speed of the tug is 7.2 m / s.