The two circles are in the shape of a cylinder. The first circle is four and a half times lower than the second

The two circles are in the shape of a cylinder. The first circle is four and a half times lower than the second, and the second is three times narrower than the first. How many times is the volume of the first circle greater than the volume of the second?

V cylinder = S base * h = pi * R ^ 2 * h;

h1 = h2 / 4.5;

R1 = 3R2;

V1 = pi * (3R2) ^ 2 * h2 / 4.5;

V2 = pi * (R2) ^ 2 * h2;

V1 / V2 = 9 / 4.5 = 2.

Answer: The volume of the first cup is twice the volume of the second cup.

Explanation: Let us express the volume of the first circle through the parameters of the second circle, knowing that the radius of the first one is three times larger, and the height is 4.5 times less. Let’s find the ratio V1 / V2, the resulting number will be the answer.