The two circles are in the shape of a cylinder. The first circle is four times higher than the second

The two circles are in the shape of a cylinder. The first circle is four times higher than the second, and the second one and a half times narrower than the first. How many times is the volume of the first circle greater than the volume of the second?

The formula for the volume of a cylinder: V = piR ^ 2h
The condition says that the first circle is four times higher than the second, and the second is already one and a half times higher, which means that the radius of the first will be one and a half times larger than the second. Substitute the values into the formula. V2 = piR ^ 2h, so V1 = pi (1.5R) ^ 2 * 4h = pi * 2.25R ^ 24h. Now, to find out how many times the volume of the first is greater than the second. Divide the volume of the first by the volume of the second. (pi * 2.25 R ^ 24h) / piR ^ 2h = all unknowns and pi will be reduced, there will remain 2.25 * 4 = 9. That is, the volume of the first mug is nine times the volume of the second.