The two motor ships go towards each other from two piers, the distance between which is 162 km.

The two motor ships go towards each other from two piers, the distance between which is 162 km. One motor ship, the speed of which is 45 km / h, left for 45 minutes. earlier than the other, whose speed is 36 km / h. How many hours after the departure of the first ship will they meet?

Let’s designate the time until the meeting, as required in the task through x (hour). Then the second motor ship passed only (x – 3/4) hour, here 45 minutes = 3/4 hours. Knowing the speed of both ships, and the time until the meeting, we will make the following equality:

45 * x + 36 * (x – 3/4) = 162; 45 * x + 36 * x = 162 + 27; 81 * x = 189; whence x = 189/81 = 21/9 = 7/3 = 2 1/3 hours = 2 hours 20 minutes.

The time before the meeting of the second boat is early: 2 hours 20 minutes – 45 minutes = 1 hour 35 minutes = 1 7/12 hours.

Check: 45 * 2 1/3 + 36 * 1 7/12 = 45 * 7/3 + 36 * 19/12 = 105 + 57 = 162 (km).



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