The two protons are 10 ^ -6 m apart. determine the strength of their interaction.

Problem data: r (distance at which the protons are located) = 10 ^ -6 m; we will assume that the protons are in a vacuum (in air).

Reference values: q (charge of one proton) = 1.6 * 10 ^ -19 C; k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2.

To determine the strength of the interaction of two protons, we will use the formula: F = k * q1 * q2 / r ^ 2 = k * q ^ 2 / r ^ 2.

Calculation: F = 9 * 10 ^ 9 * (1.6 * 10 ^ -19) ^ 2 / (10 ^ -6) ^ 2 = 230.4 * 10 ^ -18 N (230.4 aH).

Answer: The force of interaction is 230.4 aN.