# The two rectangles are the same width. The length of the first rectangle is 20 cm, the length of the second

The two rectangles are the same width. The length of the first rectangle is 20 cm, the length of the second is 24 cm. The area of the first rectangle is 48 cm2 less than the area of the second rectangle. Find the width of the rectangles.

1. Let’s denote the width of the rectangles through X cm.

2. Then the area of the first rectangle is S1 = 20 * X cm ^ 2.

3. The area of the second rectangle S2 = 24 * X cm ^ 2.

4. By the condition of the problem, S1 = S2 – 48.

5. Substitute the expressions for S1 and S2. We get the equation: 20 * X = 24 * X – 48.

6. Combine the terms with X. We get: 4 * X = 48.

7. Divide both sides of the equation by 4. We get: X = 12.

Answer: the width of the rectangles is 12 cm.

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