The two rectangles have equal areas; the first rectangle is 16 cm long and 12 cm wider than the length;
April 4, 2021 | education
| The two rectangles have equal areas; the first rectangle is 16 cm long and 12 cm wider than the length; the second rectangle is 32 cm long. Find the width of the second rectangle: What is the even side of a square that has the same area as these rectangles?
1. The first step is to calculate the width of the rectangle:
16 – 12 = 4 cm.
2. Let’s calculate the area of the first rectangle:
16 * 4 = 64 cm2
By the condition of the problem, the area of the second rectangle is 64 cm2
3. Calculate the width of the second rectangle:
64: 32 = 2 cm.
4. Calculate the side of a square with the same area as this rectangle:
√64 = 8 cm.
Answer: the width of the second rectangle is 2 centimeters, the side length of a square with the same area is 8 centimeters.
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