The two rectangles have equal areas. The length of the first rectangle is 16 cm, and its width is 12 cm
| June 29, 2021 | education
The two rectangles have equal areas. The length of the first rectangle is 16 cm, and its width is 12 cm less than its length. The length of the second rectangle is 32 cm. Find the width of the second rectangle.
1. According to the condition of the problem, the length of the first rectangle is 16 cm.
2. Determine what the width of the first rectangle is equal to if it is 12 cm less than its length.
16 – 12 = 4 cm.
3. Let’s calculate the area of the first rectangle by multiplying its length by its width.
16 * 4 = 64 cm ^ 2.
4. Since we know that the area of the second rectangle is equal to the area of the first, then it is also equal to 64 cm ^ 2. Let’s calculate what the width of the second rectangle is if its length is 32 cm.
64/32 = 2 cm.
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