The two rectangles have the same area equal to 96 cm2. The length of the first rectangle is 16 cm, its width is 2 cm

The two rectangles have the same area equal to 96 cm2. The length of the first rectangle is 16 cm, its width is 2 cm more than the width of the second rectangle. Find the length and width of the second rectangle.

Given:
S₁ = S₂ = 96 cm²
a₁ = 16 cm
b₂ = b₁-2 cm
a₂ =? cm
b₂ =? cm
Decision
The area of the rectangle is: S = a * b
1) b = S: a = 96: 16 = 6 (cm) – the width of the first rectangle.
2) b₂ = b₁-2 cm = 6-2 = 4 (cm) – the width of the second rectangle.
3) a = S: b = 96: 4 = 24 (cm) – the length of the second rectangle.
ANSWER: The second rectangle is 24 cm long and 4 cm wide.