The two rectangles have the same area. The length of the first is 18cm, width is 3cm.

The two rectangles have the same area. The length of the first is 18cm, width is 3cm. Find the width of the second rectangle if its length is 2 times less than the length of the first rectangle.

Let’s find the width of the second rectangle, provided that its length is 2 times shorter than that of the first, the dimensions of which are: 18 cm – length, 3 cm – width, while the areas are the same.

First of all, we find the area, according to the formula:

S = a * b = 3 * 18 = 54 cm².

The length of the second: 18: 2 = 9 cm. Substitute the known values into the formula:

54 cm² = 9 cm * x. To find the second factor, you need to divide the product by the first:

x = 54: 9 = 6.

Therefore, the width of the second rectangle = 6 cm.