The two sides of the quadrilateral are 2 and 7, and one of the diagonals has a length of 4 and divides this quadrilateral into two isosceles triangles. What is the smallest perimeter this quadrangle can have?
If we designate two non-adjacent sides as 2 and 7, and divide them with a diagonal, then the other two sides will also be 2 and 7, because the diagonal will be the base of an isosceles triangle.
Therefore, the perimeter will be = 2 + 2 + 7 + 7 = 18 cm.
Answer: 18 cm.
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