The two sides of the triangle are equal to each other, and the third side of the triangle is 2 cm larger
The two sides of the triangle are equal to each other, and the third side of the triangle is 2 cm larger than each of them. The area of the square built on the larger side of the triangle is 36 cm2. Find the area of a rectangle built on the smaller side of the triangle if one of the sides of the rectangle is 2 times larger than its other side. Consider different cases.
Since the area of the square built on the larger side of the triangle is 36 cm², the larger side of the triangle is √36 = 6 cm. The larger side in this triangle is the base.
If the large side of the triangle is 2 cm larger than the other side, then the second (and third) side is 6 – 2 = 4 cm.
On this side, a rectangle is built, the sides of which differ by two times.
Suppose that 4 cm is the large side, then the smaller side of the rectangle will be 2 cm, the area is: S = 4 * 2 = 8 cm².
Suppose that 4 cm is the smaller side, then the larger side is 8 cm, the area will be 4 * 8 = 32 cm².
Answer: the area of the rectangle is 8 cm² or 32 cm².