The two sides of the triangle have the same length, equal to 60 inches. The perimeter of the triangle

The two sides of the triangle have the same length, equal to 60 inches. The perimeter of the triangle is 1600 cm. Find the length of the third side.

Let’s convert 1600 cm to dm.
1 dm – 10 cm.
1600 cm ÷ 10 = 160 dm.
The perimeter of any geometric figure is equal to the sum of the lengths of its sides.
The problem statement says that the two sides of a triangle have the same length, which means that we are given an isosceles triangle. In an isosceles triangle, the sides are equal to each other.
We need to find the base of the isosceles triangle.
Let’s write down the formula for the perimeter of an isosceles triangle:
P = 2a + b,
where a is the lateral side, b is the base of the isosceles triangle.
Find the base, b from the formula for the perimeter:
b = P – 2a.
b = 160 – (2 × 60) = 160 – 120 = 40 dm.
Answer: the third side of the triangle is 40 in.