The two vessels contain a different gas. The mass of each gas molecule in the first vessel is equal to m

The two vessels contain a different gas. The mass of each gas molecule in the first vessel is equal to m, and in the second vessel – 4m. The mean square velocity of the molecules in the first vessel is V, and the second vessel is V / 2. If the absolute temperature of the gas in the first vessel is equal to T, then in the second vessel it is equal to?

We know that according to the condition, the mass of molecules in the first vessel is m1 = m, in the second m2 = 4 * m. The root mean square velocity in the first vessel is v1 = v, and in the second – v2 = V / 2. Find the temperature in vessel number two. We know that the root mean square speed is determined by the formula:
V = √3 * k * T / m;
Let’s compose the ratio:
V1 / (V2 / 2) = √T1 * m2 / T2 * m1;
1/2 = √4 * T1 / T2;
T1 = 2T2
Answer: the temperature in the second vessel is twice as high.



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