The ultrasonic signal returned after bouncing off the seafloor after 0.2 s. The speed of ultrasound
| April 3, 2021 | education
The ultrasonic signal returned after bouncing off the seafloor after 0.2 s. The speed of ultrasound in water is approximately 1500 m / s. The depth of the sea in this place is …
Initial data: t (time of movement of the ultrasonic signal) = 0.2 s; V (ultrasound velocity in water) ≈ 1500 m / s.
1) Since the ultrasonic signal returned after reflecting from the bottom, the distance that the ultrasonic signal traveled is equal to twice the depth of the sea. Therefore, the time of movement of the ultrasonic signal to the bottom is: t1 = t / 2 = 0.2 / 2 = 0.1 s.
2) Calculate the sea depth: S = V * t1 = 1500 * 0.1 = 150 m.
Answer: The depth of the sea is 150 meters.
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