The urn contains 10 red, 7 yellow and 8 green balls. One ball is taken out of the urn at random.
| September 16, 2021 | education
The urn contains 10 red, 7 yellow and 8 green balls. One ball is taken out of the urn at random. What is the probability that all 10 red balls are left in the urn?
In order for all red balls to remain in the urn, the green or yellow ball must be removed. Let’s find the probability of this, knowing that the probability is the number of successful outcomes (that is, green and yellow balls) to the total number of balls.
Number of green and yellow balls: 7 + 8 = 15.
Total number of balls: 7 + 8 + 10 = 25.
Then the probability that the red ones remain:
p = 15/25 = 0.6.
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