The urn contains 5 white, 4 green and 3 red balls. Draw one ball at random, find the probability that it is either not green or blue.
February 1, 2021 | education
| To solve this problem, you must use the formula for the classical definition of probability:
P (A) = m / n,
Where P (A) is the probability of the event A of interest to us, that is, the extraction of a ball of a certain color, m is the number of outcomes favorable to the event, n is the number of all equally possible outcomes of the test. Let’s define the value of n:
n = 5 + 4 + 3 = 12;
1) In order to determine the probability that the removed ball is not green, we determine the number of non-green balls in the urn:
m = 5 + 3 = 8.
Then:
P (A) = 8/12 = 0.667.
2) In order to determine the probability that the removed ball is not blue, we determine the number of non-blue balls in the urn:
m = 5 + 4 + 3 = 12.
Then:
P (A) = 12/12 = 1.
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