The vapor density of a monobasic carboxylic acid in terms of hydrogen is 37. What is the mass of potassium

| March 9, 2021 | education

The vapor density of a monobasic carboxylic acid in terms of hydrogen is 37. What is the mass of potassium hydroxide, which is required to neutralize 3.81 g of this acid?

1. Let’s write down the general formula for a monobasic carboxylic acid:

CnH2n + 1COOH;

2.Calculate the molecular weight of the acid:

Mr (CnH2n + 1COOH) = DH2 (CnH2n + 1COOH) * Mr (H2) = 37 * 2 = 74;

3. find the formula of carboxylic acid:

12n + 2n +1 + 12 + 33 = 74;

14n = 28;

n = 2, hence the formula C2H5COOH;

4. Let’s compose the equation of neutralization of propionic acid with potassium hydroxide:

C2H5COOH + KOH → C2H5COOK + H2O;

5.Calculate the amount of acid:

n (C2H5COOH) = m (C2H5COOH): M (C2H5COOH) = 3.81: 74 = 0.0515 mol;

6.determine the amount of potassium hydroxide and find its mass:

n (KOH) = n (C2H5COOH) = 0.0515 mol;

m (KOH) = n (KOH) * M (KOH);

M (KOH) = 39 + 17 = 56 g / mol;

m (KOH) = 0.0515 * 56 = 2.884 g.

Answer: 2.884 g.



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