The vertices A (-3; -4) are known in the ABC triangle; B (l; -2) and C (7; -2). Equate the centerline parallel

The vertices A (-3; -4) are known in the ABC triangle; B (l; -2) and C (7; -2). Equate the centerline parallel to the side of the speaker.

1. Let M and N be the midpoints of sides AB and CB of triangle ABC, respectively. Let’s find their coordinates:

A (-3; -4);
AT 12);
C (7; -2);
x (M) = (x (A) + x (B)) / 2 = (-3 + 1) / 2 = -2/2 = -1;
y (M) = (y (A) + y (B)) / 2 = (-4 – 2) / 2 = -6/2 = -3;
M (-1; -3);
x (N) = (x (C) + x (B)) / 2 = (7 + 1) / 2 = 8/2 = 4;
y (N) = (y (C) + y (B)) / 2 = (-2 – 2) / 2 = -4/2 = -2;
N (4; -2).
2. MC – the middle line connecting the midpoints of the sides. Let’s compose its equation:

M (-1; -3);
N (4; -2);
(y – y (M)) / (x – x (M)) = (y (N) – y (M)) / (x (N) – x (M));
(y + 3) / (x + 1) = (-2 + 3) / (4 + 1);
(y + 3) / (x + 1) = 1/5 = 0.2;
y + 3 = 0.2 (x + 1);
y = 0.2x + 0.2 – 3;
y = 0.2x – 2.8.
Answer: y = 0.2x – 2.8.