The vertices of the ABC triangle divide the circle in the ratio 1: 3: 5. Find the angles of this triangle

The vertices of the triangle divide the circle into arcs

360 / (1 + 3 + 5) = 360/9 = 40, 40 * 3 = 120 and 40 * 5 = 200 gr.

The angles of the triangle rest on these arcs and are equal to:

40/2 = 20, 120/2 = 50 and 200/2 = 100 gr.



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