The vertices of the triangle ABC have coordinates A (-5; 13), B (3; 5), C (-3; -1) find the coordinates

The vertices of the triangle ABC have coordinates A (-5; 13), B (3; 5), C (-3; -1) find the coordinates of the midpoints of the sides of the triangle.

Let us denote the midpoints of segments AB, BC, CA by points M, N, K.

The coordinates of the midpoint of the segment are equal to half the sum of the corresponding coordinates of the extreme points:

XM = (XA + XB) / 2 = (-5 + 3) / 2 = -1;

YM = (YA + YB) / 2 = (13 + 5) / 2 = 9;

XN = (XB + XC) / 2 = (3 – 3) / 2 = 0;

YN = (YB + YC) / 2 = (5 – 1) / 2 = 2;

XK = (XC + XA) / 2 = (-3 – 5) / 2 = -4;

YK = (YC + YA) / 2 = (-1 + 13) / 2 = 6;

Answer: M (-1, 9), N (0, 2), K (-4, 6).