The vessel contains kerosene with a density of 800 kg / m ^ 3, a piece of copper was placed

The vessel contains kerosene with a density of 800 kg / m ^ 3, a piece of copper was placed in it with a buoyancy force of 160 N. Find the volume of a piece of copper?

Given:

ro = 800 kg / m3 (kilogram per cubic meter) is the density of the kerosene in the vessel;

F = 160 Newton – the magnitude of the buoyancy force acting on a piece of copper placed in kerosene;

g = 9.8 N / kg (Newton per kilogram) is the acceleration of gravity.

It is required to determine V (m3) – the volume of a piece of copper.

Since the density of copper is greater than the density of kerosene, the piece of copper will be completely immersed in kerosene. Then, to determine its volume, you must use the following formula:

F = ro * g * V, from here we find that:

V = F / (ro * g) = 160 / (800 * 9.8) = 160/7840 = 0.02 m3 (the result has been rounded to one decimal place).

Answer: the volume of a piece of copper is 0.02 m3.