The vessel holds 900 grams of kerosene. Find the volume of this vessel if the density of kerosene is 0.8 g / cm ^ 3.

To find the required volume of a vessel with kerosene taken, we use the formula: V = m / ρк.

Values of the variables: m is the mass of kerosene in the vessel (m = 900 g = 0.9 kg); ρк – density of kerosene (ρк = 0.8 g / cm3 = 800 kg / m3).

Let’s calculate: V = m / ρк = 0.9 / 800 = 0.001125 m3 or 1.125 dm3 (1.125 l).

Answer: The volume of the taken vessel is 1.125 liters.