The vinegar essence, which is industrially manufactured for food purposes, is 80% acetic acid.

The vinegar essence, which is industrially manufactured for food purposes, is 80% acetic acid. Calculate the mass of water that must be added to 100 g of such an essence to make 6% table vinegar?

Given:
ω1 (CH3COOH) = 80%
m1 solution (CH3COOH) = 100 g
ω2 (CH3COOH) = 6%

To find:
m (H2O) -?

Decision:
1) Calculate the mass of CH3COOH:
m1 (CH3COOH) = ω1 (CH3COOH) * m1 solution (CH3COOH) / 100% = 80% * 100/100% = 80 g;
2) The mass of CH3COOH will not change:
m2 (CH3COOH) = m1 (CH3COOH) = 80 g;
3) Calculate the mass of the resulting CH3COOH solution:
m2 solution (CH3COOH) = m2 (CH3COOH) * 100% / ω2 (CH3COOH) = 80 * 100% / 6% = 1333.3 g;
4) Calculate the mass of H2O to be added:
m (H2O) = m2 solution (CH3COOH) – m1 solution (CH3COOH) = 1333.3 – 100 = 1233.3 g.

Answer: The mass of H2O is 1233.3 g.



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