The voltage across the electric lamp is 6 V. What work is done when 12 C of electricity passes through the cross-section of the filament of this lamp? 15Cl?
Initial data: U (voltage across an electric lamp) = 6 V.
1) Perfect work when passing through the cross-section of the filament of the taken lamp of charge 12 C (q1 = 12 C): A1 = U * q1 = 6 * 12 = 72 J.
2) Perfect work when passing a charge of 15 C (q2 = 15 C): A2 = U * q2 = 6 * 15 = 90 J.
Answer: With the passage of charges of 12 Kl and 15 Kl, work will be performed at 72 J and 90 J, respectively.
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