The voltage at the ends of an iron conductor 120 cm long is 60 V. Determine the current

The voltage at the ends of an iron conductor 120 cm long is 60 V. Determine the current in the conductor if the wire cross-section is 0.025 mm 2.

According to Ohm’s Law:
I = U / R, where I is the current in the conductor, U is the voltage at the ends of the iron conductor (U = 60 V), R is the resistance of the iron conductor.
R = ρ * l / S, where ρ is the resistivity of the iron conductor (ρ = 0.098 Ohm * mm ^ 2 / m), l is the length of the iron conductor (l = 120 cm = 1.2 m), S is the cross-sectional area of the iron conductor (S = 0.025 mm ^ 2).
Let’s calculate the current in the conductor:
I = U * R = U / (ρ * l / S) = U * S / (ρ * l) = 60 * 0.025 / (0.098 * 1.2) = 12.76 A.
Answer: The current strength is 12.76 A.