The voltage at the terminals of the flashlight lamp is 6V, the resistance of the lamp spiral

The voltage at the terminals of the flashlight lamp is 6V, the resistance of the lamp spiral is 30 Ohm. What is the current strength?

Given:

U = 6 Volts – voltage at the terminals of the flashlight;

R = 30 Ohm – resistance of the torch coil.

It is required to determine I (Ampere) – the strength of the current passing through the flashlight.

To determine the current strength, you must use the following formula (Ohm’s law):

U = R * I, from here we find that:

I = U / R = 6/30 = 0.2 Ampere.

Answer: a current of 0.2 Amperes passes through the flashlight.