The voltage at the terminals of the primary winding of the transformer Ud1 = 220V, and the current Id1 = 0.6 A

| August 17, 2021 | education

The voltage at the terminals of the primary winding of the transformer Ud1 = 220V, and the current Id1 = 0.6 A. Determine the current Id2 in the secondary winding of the transformer, if the voltage at its terminals Ud2 = 12V, the efficiency of the transformer is n = 98%

Data: primary winding of the transformer (Ud1 (voltage) = 220 V; Id1 (current) = 0.6 A); secondary winding (Ud2 (voltage) = 12 V); η (efficiency of the transformer taken) = 98% (0.98).

We express the current strength in the secondary winding of the taken transformer from the formula for calculating the efficiency of the transformer: η = P2 / P1 = Ud2 * Id2 / (Ud1 * Id1), whence Id2 = Ud1 * Id1 * η / Ud2.

Calculation: Id2 = 220 * 0.6 * 0.98 / 12 = 10.78 A.

Answer: A current of 10.78 A flows in the secondary lining of the transformer taken.



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