The voltage in the flashlight is 9 V, its electrical resistance is 15 ohms. Determine the current in the coil of the flashlight.
| May 30, 2021 | education
According to Ohm’s law, the current in the coil of the flashlight will be directly proportional to the effective voltage and inversely proportional to the electrical resistance of the coil.
I = U / R, where U is the voltage in the flashlight (U = 9 V), R is the resistance of the coil of the flashlight (R = 15 ohms).
Let’s calculate the current in the coil of the flashlight:
I = U / R = 9/15 = 0.6 A.
Answer: The current in the coil of the flashlight is 0.6 A.
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