The voltage in the network is 120 V. The resistance of each of the two light bulbs included in this network is 240 ohms. Determine the current strength in each lamp with their sequential and parallel switching on.
To solve the problem, we first find the resistance of the lamps when connected in series.
To do this, we sum up the resistances of the lamps.
240 + 240 = 480 ohms.
We find the current in the network.
To do this, we divide the voltage in the network by the resistance of the two lamps.
120/480 = 0.25 A.
For parallel connection, the resistance of the lamps will be:
1/240 + 1/240 = 2/240 = 1/120 = 120 ohms.
We find the current in the network when lamps are connected in parallel.
120/120 = 1 A.
The current in each lamp will be:
1/2 = 0.5 A.
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