The voltage on the incandescent lamp is 220 V what charge passed through the filament

The voltage on the incandescent lamp is 220 V what charge passed through the filament of the lamp if at the same time 4400 J was performed.

Given:

U = 220 Volts – voltage across the filament of the incandescent lamp;

A = 4400 Joules – work done by electric current.

It is required to determine q (Pendant) – what charge passed through the lamp filament.

Let t be the time during which work A was completed.

Then the power of the electric current will be equal to:

W = A / t = 4400 / t.

The current strength will be equal to:

I = W / U = 4400 / (220 * t) = 2 / t.

The charge will be equal to:

q = I * t = 2 * t / t = 2 Pendant.

Answer: a charge equal to 2 Coulomb passed through the filament of the lamp.