The voltmeter and ammeter included in the electrical circuit show 9V and 3A, respectively.
The voltmeter and ammeter included in the electrical circuit show 9V and 3A, respectively. The load resistance is 5 times the internal resistance of the current source. What is the resistance of the external circuit?
U = 9 V.
I = 3 A.
Rv = 5 * r.
Rв -?
1.Write Ohm’s law for a closed circuit: I = U / (Rv + r), where U is the voltage that the voltmeter shows, I is the current that the ammeter shows, Rv is the external resistance, r is the internal resistance of the current source.
Since Rв = 5 * r by condition, the formula will take the form:: I = U / (5 * r + r).
I = U / 6 * r.
r = U / 6 * I.
Let us express the external resistance of the circuit: Rv = 5 * r = 5 * U / 6 * I.
Rv = 5 * 9 V * 6 * 3 A = 2.5 ohms.
Answer: the external resistance of the circuit is Rv = 2.5 ohms.