The volume fraction of methane in natural gas is 92%. what volume of this gas mixture will contain 4.6 ml of methane.

1. The volume of the mixture is found by the formula:

V (gas mixture) = (V / ω) * 100%, where V is the volume; ω (omega) – mass fraction (in percent).

2. Find the volume of the gas mixture:

V (gas mixture) = (4.6 ml / 92%) * 100% = 5 ml.

Answer: The volume of the gas mixture with 4.6 ml of methane is 5 ml.



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