The volume of a piece of iron is 0.1 dm3. What buoyancy force will act on it when fully immersed

The volume of a piece of iron is 0.1 dm3. What buoyancy force will act on it when fully immersed in water? In kerosene?

Given: V (volume of a piece of iron taken) = 0.1 dm3 (0.1 * 10-3 m3).

Constants: g (acceleration of gravity) = 9.8 m / s2; ρw (water density) = 1000 kg / m3; ρк (kerosene density) = 800 kg / m3.

1) Immersion of a piece of iron in water: Fa1 = ρw * g * V = 1000 * 9.8 * 0.1 * 10-3 = 0.98 N.

2) Immersion in kerosene: Fa2 = ρк * g * V = 800 * 9.8 * 0.1 * 10-3 = 0.784 N.

Answer: A lump of iron when fully immersed in water, kerosene will have a buoyancy force of 0.98 N and 0.784 N, respectively.