The volume of a piece of tin is 0.2 m3. What buoyancy force will act on it when it is completely immersed in water?

The buoyancy force of Archimedes will act on a piece of tin in water, equal to:
Fа = ρ * g * V, where Fа is the value of the Archimedes force (N), ρ is the density of water (ρ = 1000 kg / m ^ 3), g is the acceleration of gravity (we take g = 9.8 m / s ^ 2 ), V is the volume of the immersed part of a piece of tin (V = 0.2 m ^ 3).
Let’s calculate the buoyancy force:
Fa = ρ * g * V = 1000 * 9.8 * 0.2 = 1960 N.
Answer: The buoyant force is 1960 N.

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