The volume of air at a temperature of 0 degrees C is equal to 100 liters. What will its volume be at a temperature of 273 degrees C.

t1 = 0 C.
V1 = 100 L = 0.1 m ^ 3.
t2 = 273 C.
P = const
V2 -?
Let’s convert the temperature to degrees Kelvin: T = t + 273 K.
T1 = 0 C + 273 K = 273 K.
T2 = 273 C + 273 K = 546 K.
At P = const, the Gay-Lussac law is valid: V1 / T1 = V2 / T2.
V2 = V1 * T2 / T1.
V2 = 0.1 m ^ 3 * 546 K / 273 K = 0.2 m ^ 3.
Answer: the volume of air will be V2 = 0.2 m ^ 3.