# The volume of butane is equal to 22.4 liters of combustion to find the mass of the volume of oxygen.

August 28, 2021 | education

| The butane oxidation reaction is described by the following chemical reaction equation.

2C4H10 + 13O2 = 8CO2 + 10H2O;

According to the coefficients of this equation, 13 oxygen molecules are required to oxidize 2 butane molecules. In this case, 8 molecules of carbon dioxide are synthesized.

Let’s calculate the amount of butane available.

To do this, we divide the available gas volume by the volume of 1 mole of ideal gas under normal conditions.

N C4H10 = 22.4 / 22.4 = 1 mol;

The amount of oxygen will be.

N O2 = 1 x 13/2 = 6.5 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V O2 = 6.5 x 22.4 = 145.6 liters;

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