The volume of carbon dioxide formed during the combustion of 5 liters of propane.
July 11, 2021 | education
| The propane oxidation reaction is described by the following chemical reaction equation.
C3H8 + 5O2 = 3CO2 + 4H2O;
According to the coefficients of this equation, 5 oxygen molecules are required to oxidize 1 propane molecule. This synthesizes 3 molecules of carbon dioxide.
Let’s calculate the amount of propane available.
To do this, we divide the available gas volume by the volume of 1 mole of ideal gas under normal conditions.
N C3H8 = 5 / 22.4 = 0.223 mol; The amount of carbon dioxide will be.
N CO2 = 0.223 x 3 = 0.669 mol;
Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.
Its volume will be: V CO2 = 0.669 x 22.4 = 15 liters;
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