The volume of carbon dioxide generated by the interaction of 10 g of calcium carbonate with

| June 25, 2021 | education

The volume of carbon dioxide generated by the interaction of 10 g of calcium carbonate with a solution containing 36.5 g of hydrochloric acid is equal to.

Let’s find the amount of acid substance by the formula:

n = m: M.

M (HCl) = 35 + 1 = 36 g / mol.

n = 36.5 g: 36 g / mol = 1.01 mol.

Find the amount of calcium carbonate substance:

M (CaCO3) = 100 g / mol.

n = 10 g: 100 g / mol = 0.1 mol.

Hydrochloric acid is given in excess.

The amount of carbon dioxide is calculated by the deficiency (calcium carbonate).

Let’s compose the reaction equation, find the quantitative relationships of substances

CaCO3 + 2HCl = CaCl2 + CO2 ↑ + H2O.

According to the reaction equation, there is 1 mole of gas per mole of calcium carbonate. Substances are in quantitative ratios 1: 1.

The amount of substance will be the same.

n (CO2) = n (CaCO3) = 0.1 mol.

Let’s find the volume of carbon dioxide.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 0.1 mol × 22.4 L / mol = 2.24 L.

Answer: 2.24 liters.



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