The volume of carbon dioxide generated during the combustion of 11.2 liters of methane CH4.

Let’s write down the solution step by step according to the conditions:
1. Let’s make the equation for methane:
1 mol 1 mol;
СН4 + 2О2 = СО2 + 2Н2О – combustion reaction, carbon dioxide was obtained;
2. Let’s make a proportion according to the equation:
1 mol of gas at normal level – 22.4 liters;
X mol (CH4) – 11.2 liters. hence, X mol (CH4) = 1 * 11.2 / 22.0.5 mol;
Y (CO2) = 0.5 mol since according to the equation the amount of these substances is 1 mol.
3. Find the volume of carbon monoxide (4):
V (CO2) = 0.5 * 22.4 = 11.2 liters.
Answer: the product of the combustion reaction, CO2, was obtained in a volume of 11.2 liters.