The volume of carbon dioxide obtained by burning 10 liters of methane in 20 liters of oxygen is …

Let’s execute the solution:

In accordance with the condition of the problem, we write down the equation of the process:
V = 10 l; V = 20 l; X l -?

СН4 + 2О2 = СО2 + 2Н2О + Q – combustion, carbon dioxide, water, heat are released;

Proportions:
1 mol of gas at normal level – 22.4 liters;

X mol (CH4) – 10 liters from here, X mol (CH4) = 1 * 10 / 22.4 = 0.45 mol (the substance is in short supply);

Y (CO2) = 0.45 mol since the amount of substances is 1 mol.

1 mole of gas at normal level – 22.4 liters;

X mol (O2) – 20 liters from here, X mol (O2) = 1 * 20 / 22.4 = 0.9 mol (substance in excess).

Calculations are made for the substance in deficiency.

Find the volume of the oxide:
V (CO2) = 0.45 * 22.4 = 10 l

Answer: the volume of carbon dioxide is 10 liters.