The volume of carbon dioxide required for the reaction with lime water to form 162 g of acidic salt is…

1.Let’s find the amount of calcium bicarbonate substance Ca (HCO3) 2.

n = m: M

M (Ca (HCO3) 2) = 40 + 2 (1 + 12 + 16 × 3) = 162 g / mol.

n = 162 g: 162 g / mol = 1 mol.

2. We compose the reaction equation, we determine in what quantitative ratios are calcium bicarbonate and carbon dioxide.

Ca (OH) 2 + 2CO2 = Ca (HCO3) 2.

The reaction involves 2 moles of carbon dioxide and 1 mole of salt, that is, they react 2: 1, so the amount of carbon dioxide will be 2 times more than the amount of salt.

n (CO2) = 1 mol × 2 = 2 mol.

3. V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V (CO2) = 2 mol × 22.4 L / mol = 44.8 L.

Answer: 44.8 liters.