The volume of carbon dioxide that is generated by burning 5 liters of carbon monoxide is equal to ..

Let’s implement the solution:

According to the condition of the problem, we write the equation of the process:
V = 5 l Chl -?

2СО + О2 = 2СО2 – ОВР, carbon dioxide is released.

Proportion:
1 mol of gas at normal level – 22.4 liters;

X mol (CO) – 5 liters from here, X mol (CO) = 1 * 5 / 22.4 = 0.2 mol;

Y (CO2) = 0.2 mol since the amount of substances is 2 mol.

Find the volume of the product:
V (CO2) = 0.2 * 22.4 = 4.48 L

Answer: obtained carbon monoxide (4) with a volume of 4.48 liters