The volume of carbon monoxide (IV) required to obtain an acidic salt when reacted with 16 grams of sodium hydroxide.

First, we write down the reaction equation, if it is known that carbon monoxide and sodium hydroxide enter into the reaction, as a result an acidic salt is obtained.
CO2 + NaOH = NaHCO3.
Next, we find the amount of sodium hydroxide substance, use the following formula.
n = m / M.
Where n is the amount of substance.
m is the mass of the substance.
M is the molar mass of the substance.
First we find M.
M (NaOH) = 23 + 1 + 16 = 40 g / mol.
n (NaOH) = 16g / 40g / mol = 0.4 mol.
We make the proportion.
x mol CO2 – 0.4 mol NaOH.
1 mol СО2 – 1 mol NaOH.
n (CO2) = 1 × 0.4 ÷ 1 = 0.4 mol CO2.
V (CO2) = n * Vm = 0.4 mol × 22.4 l / mol = 8.96 l.
Answer: in, V (CO2) = 8.96 liters.