The volume of gas as a result of the isobaric process decreased by 10 liters, and the temperature
| August 17, 2021 | education
The volume of gas as a result of the isobaric process decreased by 10 liters, and the temperature dropped by 1.2 times. Determine the starting gas volume.
Data: ΔV (gas volume reduction) = 10 l (V2 = V1 – 10); ΔT (lowering the gas temperature) = 1.2 p. (T1 = 1.2T2); isobaric process (P = const).
The initial gas volume at constant pressure can be determined from the ratio: V1 / T1 = V2 / T2.
V1 / 1.2T2 = (V1 – 10) / T2.
V1 = 1.2V1 – 12.
0.2V1 = 12 and V1 = 60 HP
Answer: The initial gas volume was 60 liters.
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