The volume of hydrogen at a pressure of 0.96 kPa is 50 liters. What volume will hydrogen have

The volume of hydrogen at a pressure of 0.96 kPa is 50 liters. What volume will hydrogen have at a pressure of 1.8 kPa if the gas temperature has not changed?

Let us write down the Mendeleev-Clapeyron equations for two states:
p1 * v1 = m / M * R * T,

p2 * v2 = m / M * R * T

where p1 and p2 are pressure, v1 and v2 are volume, m is mass, M is mole mass, R is universal gas constant, T is temperature.

Dividing one equation by another, we get:

p1 * v1 / p2 * v2 = 1.

Express v2 from it:

v2 = p1 * v1 / p2.

We substitute the values from the condition:

v2 = 0.98 * 50 / 1.8 = 27.2 liters.

Answer: the volume of gas at the new pressure will be 27.2 liters.