The volume of hydrogen at a temperature of 50 ° C and a pressure of 0.98 • 10 ^ 5 Pa is 2.5 • 10 ^ -3 m3.

The volume of hydrogen at a temperature of 50 ° C and a pressure of 0.98 • 10 ^ 5 Pa is 2.5 • 10 ^ -3 m3. What is the volume of the same mass of hydrogen at 0 ° C and a pressure of 10 to the 5th power of Pa?

Data: T1 (initial hydrogen temperature) = 50 ºС (323 K); P1 (initial pressure) = 0.98 * 10 ^ 5 Pa; V1 (initial volume of hydrogen) = 2.5 * 10 ^ -3 m3; T2 (final temperature) = 0 ºС (273 K); P2 (final pressure) = 0.98 * 10 ^ 5 Pa.

For a constant mass of hydrogen, the ratio will be correct: P1 * V1 / T1 = P2 * V2 / T2 and V2 = P1 * V1 * T2 / (T1 * P2).

Let’s perform the calculation: V2 = 0.98 * 10 ^ 5 * 2.5 * 10 ^ -3 * 273 / (323 * 0.98 * 10 ^ 5) = 2.11 * 10 ^ -3 m3.

Answer: The volume of hydrogen will be equal to 2.11 * 10 ^ -3 m3.